Integrand size = 28, antiderivative size = 181 \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\frac {2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{7 a^2 d e^4}+\frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}}+\frac {2 \sin (c+d x)}{7 a^2 d e^3 \sqrt {e \sec (c+d x)}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )} \]
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Time = 0.18 (sec) , antiderivative size = 181, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3581, 3854, 3856, 2720} \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\frac {2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{7 a^2 d e^4}+\frac {2 \sin (c+d x)}{7 a^2 d e^3 \sqrt {e \sec (c+d x)}}+\frac {4 i e^2}{15 d \left (a^2+i a^2 \tan (c+d x)\right ) (e \sec (c+d x))^{11/2}}+\frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}} \]
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Rule 2720
Rule 3581
Rule 3854
Rule 3856
Rubi steps \begin{align*} \text {integral}& = \frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {\left (11 e^2\right ) \int \frac {1}{(e \sec (c+d x))^{11/2}} \, dx}{15 a^2} \\ & = \frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {3 \int \frac {1}{(e \sec (c+d x))^{7/2}} \, dx}{5 a^2} \\ & = \frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {3 \int \frac {1}{(e \sec (c+d x))^{3/2}} \, dx}{7 a^2 e^2} \\ & = \frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}}+\frac {2 \sin (c+d x)}{7 a^2 d e^3 \sqrt {e \sec (c+d x)}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {\int \sqrt {e \sec (c+d x)} \, dx}{7 a^2 e^4} \\ & = \frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}}+\frac {2 \sin (c+d x)}{7 a^2 d e^3 \sqrt {e \sec (c+d x)}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )}+\frac {\left (\sqrt {\cos (c+d x)} \sqrt {e \sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{7 a^2 e^4} \\ & = \frac {2 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) \sqrt {e \sec (c+d x)}}{7 a^2 d e^4}+\frac {2 e \sin (c+d x)}{15 a^2 d (e \sec (c+d x))^{9/2}}+\frac {6 \sin (c+d x)}{35 a^2 d e (e \sec (c+d x))^{5/2}}+\frac {2 \sin (c+d x)}{7 a^2 d e^3 \sqrt {e \sec (c+d x)}}+\frac {4 i e^2}{15 d (e \sec (c+d x))^{11/2} \left (a^2+i a^2 \tan (c+d x)\right )} \\ \end{align*}
Time = 1.90 (sec) , antiderivative size = 151, normalized size of antiderivative = 0.83 \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=-\frac {(e \sec (c+d x))^{5/2} \left (296 i+228 i \cos (2 (c+d x))-72 i \cos (4 (c+d x))-4 i \cos (6 (c+d x))+480 \sqrt {\cos (c+d x)} \operatorname {EllipticF}\left (\frac {1}{2} (c+d x),2\right ) (\cos (2 (c+d x))+i \sin (2 (c+d x)))-17 \sin (2 (c+d x))+128 \sin (4 (c+d x))+11 \sin (6 (c+d x))\right )}{1680 a^2 d e^6 (-i+\tan (c+d x))^2} \]
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Time = 9.96 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.14
method | result | size |
default | \(\frac {\frac {4 i \left (\cos ^{7}\left (d x +c \right )\right )}{15}+\frac {4 \sin \left (d x +c \right ) \left (\cos ^{6}\left (d x +c \right )\right )}{15}+\frac {2 \sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )}{15}+\frac {2 i F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}{7}+\frac {6 \left (\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{35}+\frac {2 i \sec \left (d x +c \right ) F\left (i \left (-\csc \left (d x +c \right )+\cot \left (d x +c \right )\right ), i\right ) \sqrt {\frac {1}{\cos \left (d x +c \right )+1}}\, \sqrt {\frac {\cos \left (d x +c \right )}{\cos \left (d x +c \right )+1}}}{7}+\frac {2 \sin \left (d x +c \right )}{7}}{a^{2} d \sqrt {e \sec \left (d x +c \right )}\, e^{3}}\) | \(206\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.09 (sec) , antiderivative size = 148, normalized size of antiderivative = 0.82 \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\frac {{\left (\sqrt {2} \sqrt {\frac {e}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}} {\left (-15 i \, e^{\left (12 i \, d x + 12 i \, c\right )} - 200 i \, e^{\left (10 i \, d x + 10 i \, c\right )} + 245 i \, e^{\left (8 i \, d x + 8 i \, c\right )} + 592 i \, e^{\left (6 i \, d x + 6 i \, c\right )} + 211 i \, e^{\left (4 i \, d x + 4 i \, c\right )} + 56 i \, e^{\left (2 i \, d x + 2 i \, c\right )} + 7 i\right )} e^{\left (\frac {1}{2} i \, d x + \frac {1}{2} i \, c\right )} - 960 i \, \sqrt {2} \sqrt {e} e^{\left (8 i \, d x + 8 i \, c\right )} {\rm weierstrassPInverse}\left (-4, 0, e^{\left (i \, d x + i \, c\right )}\right )\right )} e^{\left (-8 i \, d x - 8 i \, c\right )}}{3360 \, a^{2} d e^{4}} \]
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Timed out. \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\text {Exception raised: RuntimeError} \]
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\[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\int { \frac {1}{\left (e \sec \left (d x + c\right )\right )^{\frac {7}{2}} {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {1}{(e \sec (c+d x))^{7/2} (a+i a \tan (c+d x))^2} \, dx=\int \frac {1}{{\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^{7/2}\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^2} \,d x \]
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